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Prep 5.11.3

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This commit is contained in:
Harvey Kandola 2024-02-16 10:53:02 -05:00
parent 69940cb7f1
commit f2ba294be8
47 changed files with 169 additions and 3090 deletions
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41
vendor/github.com/go-ldap/ldap/v3/request.go generated vendored
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@ -9,8 +9,7 @@ import (
var (
errRespChanClosed = errors.New("ldap: response channel closed")
errCouldNotRetMsg = errors.New("ldap: could not retrieve message")
// ErrNilConnection is returned if doRequest is called with a nil connection.
ErrNilConnection = errors.New("ldap: conn is nil, expected net.Conn")
ErrNilConnection = errors.New("ldap: conn is nil, expected net.Conn")
)
type request interface {
@ -70,41 +69,3 @@ func (l *Conn) readPacket(msgCtx *messageContext) (*ber.Packet, error) {
}
return packet, nil
}
func getReferral(err error, packet *ber.Packet) (referral string) {
if !IsErrorWithCode(err, LDAPResultReferral) {
return ""
}
if len(packet.Children) < 2 {
return ""
}
// The packet Tag itself (of child 2) is generally a ber.TagObjectDescriptor with referrals however OpenLDAP
// seemingly returns a ber.Tag.GeneralizedTime. Every currently tested LDAP server which returns referrals returns
// an ASN.1 BER packet with the Type of ber.TypeConstructed and Class of ber.ClassApplication however. Thus this
// check expressly checks these fields instead.
//
// Related Issues:
// - https://github.com/authelia/authelia/issues/4199 (downstream)
if len(packet.Children[1].Children) == 0 || (packet.Children[1].TagType != ber.TypeConstructed || packet.Children[1].ClassType != ber.ClassApplication) {
return ""
}
var ok bool
for _, child := range packet.Children[1].Children {
// The referral URI itself should be contained within a child which has a Tag of ber.BitString or
// ber.TagPrintableString, and the Type of ber.TypeConstructed and the Class of ClassContext. As soon as any of
// these conditions is not true we can skip this child.
if (child.Tag != ber.TagBitString && child.Tag != ber.TagPrintableString) || child.TagType != ber.TypeConstructed || child.ClassType != ber.ClassContext {
continue
}
if referral, ok = child.Children[0].Value.(string); ok {
return referral
}
}
return ""
}